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In computing, the collection of four bits is called a nibble. for _ in range (int(input())): n,k=map(int,input().split()) a=list(map(int,input().split())) count=0 for i in a: if(i+k)%7==0: count+=1 ... Maximize profit using greedy logic while respecting the constraint of selling up to two items. A great Given two positive numbers B and C, what is the Do and my channel brand tech so that i will be abel to make vedios this in future for Determine the best popcorn option by comparing prices and quantities using simple logical checks. A beginner-friendly
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