![Leetcode Solution 139. Word break [Dynamic Programming]](https://i.ytimg.com/vi/_iIK7Gu7MNo/mqdefault.jpg)
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Last Updated: September 26, 2026
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neetcode.io/ - A better way to prepare for Hello guys! Here is the solution to a nice Super helpful resources: nikoo28.github.io/all-my-links/ Actual In response to some feedback received on the video: youtu.be/yr77dVf1RQA I wanted to explain the thought-process in ... This video explains how to solve the Given a string and a dictionary, return true if string can be backstreetbrogrammer Pseudo code: boolean[] dp = new boolean[s.length() + 1]; dp[s.length()] = true; for (int i = s.length() - 1; i is ... Note that you are allowed to reuse a dictionary word. My contact details Instagram :- instagram.com/frazmohammad/ Connect with me on LinkedIn ... algojs.dev - Streamline your learning today! algojs.ck.page/d4db71b424 - Exclusive DSA Course Step by step ... Given a string s and a dictionary of strings wordDict, return true if s can be segmented into a space-separated sequence of one or ...
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